java logs where to buy

Say you had an array for which the ith element was the price of a given stock on day i.design an algorithm to find the maxImum profit.You could complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, engage in multiple transactions for the same time (ie, you must sell the stock before you buy again).Test instructions: Stock

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Problem Solving Ideas:One traversal, each time a minimum buy point is found, the Java implementation is as follows: public

it again;F (N) = (m+n)!* (m-n+1)/(m+1).Because the data is too large, so the large number of Java to solveCodeImport Java.util.*;import Java.math.biginteger;public class main{public static void Main (string[] args) { int a , b; Scanner in=new Scanner (system.in); int cnt=0; while (In.hasnext ()) { cnt++; A=in.nextint (); B=in.nextint (); BigInte

Say you had an array for which the ith element was the price of a given stock on day i.design an algorithm to find the maxImum profit. You are in most of the transactions. Note:you engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). Subscribe to see which companies asked this question.Test instructions: Buy and sell stocks. You only have two chances to

type:Global[i][j]=max (Global[i-1][j],local[i][j]), that is, the day I have no transaction, and the first day of trading local[i][ J]=max (Global[i-1][j-1]+max (diff,0), Local[i-1][j]+diff) diff=price[i]-price[i-1]; Two is taken from the local i-1 day J Trade, and then add today's difference (here because local[i-1][j], for example, contains the sale of the i-1 day, so now becomes the day I sell, does not increase the number of transactions, And here whether the diff is gr

data is too large, so use the Java large number to solveCodeImport Java.util.*;import Java.math.biginteger;public class main{public static void Main (string[] args) { int a , b; Scanner in=new Scanner (system.in); int cnt=0; while (In.hasnext ()) { cnt++; A=in.nextint (); B=in.nextint (); BigInteger Ans=biginteger.one; if (a==0b==

============ Problem Description ============Dear God, do java+android development, what kind of notebook should I buy?For example, how much memory, how much CPU, as well as graphics cards and so on. The more detailed the better!Preferably with a specific model. Please recommend, thank you!============ Solution 1============Development Android configuration requirements are not high ah, my original Pentium

Title Description:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You could complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, engage in multiple transactions for the same time (ie, you must sell the stock before you buy again).Problem Solving Ideas:When the day after t

Title:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Algorithm Analysis:Use the general algorithm "best time to Buy and Sell Stock IV" to change K to 2 OKAC Code: [Leetcode] [

Title: Rooster 5 Text Money One, hen 3 money A, Chick 3 only a penny,Buy 100 chickens with 100 cents, among them cocks, hens, chickens all must have, ask the rooster, hen, chicken to buy how many only just to make up 100 text money.Solution: Set, Rooster x only, hen y only, chick Z only.x+y+z=1005x+3y+1/3z=100(0We use the enumeration methodThe code is as follows:public class teststatic{public static void Ma